60. Solution to Chemistry Problem
📂 Chemistry
👤 Derkach
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1. The electrical conductivity of potassium iodate (KIO₃) was measured at 25°C [66]. The data are presented in the table below; C – concentration of potassium iodate (g-equiv·L⁻¹); A – equivalent conductivity of the solution corrected for water. Determine Λ₀ – the limiting equivalent conductivity of KIO₃.
C (g-equiv·L⁻¹) A (S·cm²/mol)
0.00018265 113.07
0.00035295 112.61
0.00070430 111.91
0.00099845 111.45
0.0017117 110.45
0.0025362 109.78
0.0032859 109.19
0.0039118 108.78
2. Based on the calculations from part 1, determine the conductivity at infinite dilution for sodium iodate and lithium iodate. Use the conductivity data at infinite dilution for the ions:
Li⁺: 36.68 S·cm²/mol
Na⁺: 50.10 S·cm²/mol
K⁺: 73.50 S·cm²/mol
3. Calculate the conductivities of lithium iodate and sodium iodate at C = 0.002 mol/L.
C (g-equiv·L⁻¹) A (S·cm²/mol)
0.00018265 113.07
0.00035295 112.61
0.00070430 111.91
0.00099845 111.45
0.0017117 110.45
0.0025362 109.78
0.0032859 109.19
0.0039118 108.78
2. Based on the calculations from part 1, determine the conductivity at infinite dilution for sodium iodate and lithium iodate. Use the conductivity data at infinite dilution for the ions:
Li⁺: 36.68 S·cm²/mol
Na⁺: 50.10 S·cm²/mol
K⁺: 73.50 S·cm²/mol
3. Calculate the conductivities of lithium iodate and sodium iodate at C = 0.002 mol/L.
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