71. For the anaerobic type of nutrition process C6H12O6 = 2C2H5OH 2CO2 ΔG0 = -243.63 kJ/mol, and for the aerobic type of nutrition C6H12O6 6O2 = 6CO2 6H2O ΔG0 = -2872.3 kJ/mol. Which process is the most efficient in terms of the use of α-D-glucose?

If the file does not open for you, install the Rar archiver program. Inside the archive, the solution is in WORD format.