1. Equivalent electrical conductivity of 1.59 ⋅10-4 M acetic acid at 25°C λ = 12.77 S⋅cm2/mol-equiv. Calculate the dissociation constant K and the specific electrical conductivity of the solution (S⋅cm-1), if the ion mobility λ0H = 349.8 S⋅cm2/mol-equiv. and λ0CH3COO– = 40.9 S⋅cm2/mol-eq.

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.