3. The enthalpy of decomposition of calcium carbonate at 900 C and a pressure of 1 atm is 178 kJ/mol. Calculate the amount of heat absorbed during the decomposition of 1 kg of calcium carbonate at 1000 C and 1 atm, if the dependences of molar heat capacities on temperature are given (J / (mol * K):
Cp (CaCO3 (tv)) \u003d 104.5 21.92 * 103T-25.94 * 105T-2
Cp (CaO (tv)) \u003d 49.63 4.52 * 10-3T-6.95 * 105T-2

Cp(CO2(g))=44.14 9.04*10-3T-8.53*10-3T

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