67. What mass of monochloroacetic acid (M = 94.50 g / mol) should be dissolved in 500 ml of water, so that after treatment with 20 ml of the resulting solution with an alcoholic solution of KOH, the formed Cl- is precipitated in the form of AgCl by adding 50 ml of a 0.100 M solution of AgNO3 and spent on titration of excess silver 18.50 ml 0.100M NH-4SCN?

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.