88. Solving a chemistry problem
📂 Coursework
👤 Derkach
Product Description
273. Reactions proceed according to the schemes:
K2Cr2O7 KI H2SO4 = Cr2(SO4)3 I2 K2SO4 H2O;
FeS HNO3 = Fe(NO3)3 S NO2 H2O
using the ion-electron method, equalize these reactions. For each reaction, determine the equivalent of the oxidizing agent and reducing agent.
K2Cr2O7 KI H2SO4 = Cr2(SO4)3 I2 K2SO4 H2O;
FeS HNO3 = Fe(NO3)3 S NO2 H2O
using the ion-electron method, equalize these reactions. For each reaction, determine the equivalent of the oxidizing agent and reducing agent.
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