106. Solving a chemistry problem
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212. The boundary of sedimentation (the boundary between the cloudy and transparent parts of the solution) of the enzyme in an aqueous solution at 20.6°C was observed as a function of time at a centrifuge speed of 56050 min¯¹
t, min 0 20 40 60 80 100 120 140
x*, cm 5.911 6.0217 6.1141 6.2068 6.304 6.4047 6.5133 6.6141
x* - distance from the axis of rotation
Based on these data, determine the sedimentation coefficient and the molar mass of the enzyme, knowing that the friction coefficient f is 8.24*10¯¹¹ kg/s and the ascent coefficient (1 – Vsp ρ0) = 0.256
t, min 0 20 40 60 80 100 120 140
x*, cm 5.911 6.0217 6.1141 6.2068 6.304 6.4047 6.5133 6.6141
x* - distance from the axis of rotation
Based on these data, determine the sedimentation coefficient and the molar mass of the enzyme, knowing that the friction coefficient f is 8.24*10¯¹¹ kg/s and the ascent coefficient (1 – Vsp ρ0) = 0.256
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