To determine the aluminum content, a sample of Al(NO3)3*H2O crystalline hydrate weighing 1.823 g was dissolved in water in a 100.0 ml volumetric flask. An excess of magnesium complexonate was added to an aliquot of this solution (V = 10.0 ml). 18.55 ml of 0.02503M EDTA solution was used for titration of the released Mg ions. Find the mass fraction of Al(NO3)3 in its crystalline hydrate. What titration method was used?

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.