1. Calculate the mass of a sample containing approximately 65% MnO2 so that after reaction with 50.00 ml of 0.1000 N. H2C2O4 (feq=1/2), its excess was titrated with 25.00 ml of KMnO4 solution (1.00 ml of KMnO4 solution is equivalent to 1.05 ml of H2C2O4 solution). (answer 0.1588 g).

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