Решение задачки номер 2

📂 Mathematics 👤 Derkach

Product Description

2.0 В растворе сульфата железа (III) осадили железо аммиаком в виде Fe(OH)3 и прокалили. Вес прокаленного осадка Fe2O3 оказался равным 0,3288 г. Вычислить содержание железа(III) в растворе.
Price: $1.25
Seller: Derkach
Category: Mathematics
Currency: USD

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