The specific electrical conductivity of a saturated solution of BaSO4 is 3.48*10-4 S/m, and that of a solvent (water) is 0.5*10-4 S/m. Calculate the solubility product of this salt, taking the molar conductivity of BaSO4 in a saturated solution equal to the limiting conductivity (limiting conductivities of Ba2 and SO42- ions are 0.012726 and 0.016004 S*m2*mol-1, respectively).

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