DHS - 3.2
No. 1.16. Vertices ∆АВС are given: А (6; –9); B (10; –1); C (–4; 1). Find: a) Equation side AB; b) Equation of height CH; c) the median AM equation; d) the intersection point N of the median AM and the height of the SN; e) the equation of a straight line passing through the vertex C and parallel to the side AB; e) distance from point C to straight line AB.
No. 2.16. Make an equation of the height drawn through the vertex A of the triangle ABC, knowing the equations of its sides. AB: 2x - y - 3 = 0; AC: x + 5y - 7 = 0; BC: 3x - 2y + 13 = 0.