Dievsky V.A - Solution of problem D4 variant 15 task 2
📂 For Education Students
👤 Михаил_Перович
Product Description
D4-15 (Task 2) Dievskiy
For the diagram shown in the figure using the Lagrange principle, determine the force F (in the presence of friction - the maximum value of this value), at which the mechanical system will be in equilibrium. Initial data: weight of the load G = 20 kN, torque M = 1 kNm, radius of the drum R2 = 0.4 m (in the double drum there is also r2 = 0.2 m), angle α = 300 and slip coefficient f = 0.5 . Unmatched blocks and skating rinks are considered weightless. Friction on the axes of the drum and blocks is neglected.
For the diagram shown in the figure using the Lagrange principle, determine the force F (in the presence of friction - the maximum value of this value), at which the mechanical system will be in equilibrium. Initial data: weight of the load G = 20 kN, torque M = 1 kNm, radius of the drum R2 = 0.4 m (in the double drum there is also r2 = 0.2 m), angle α = 300 and slip coefficient f = 0.5 . Unmatched blocks and skating rinks are considered weightless. Friction on the axes of the drum and blocks is neglected.
Related Products
C2 Option 06 termehu of Reshebnik Yablonsky AA 1978
Seller: TerMaster
C2 Option 04 termehu of Reshebnik Yablonsky AA 1978
Seller: TerMaster
Dievsky V.A. - Solution of problem K2 variant 2 (K2-02)
Seller: Михаил_Перович
Dievsky V.A. - Solution of task K2 variant 3 (K2-03)
Seller: Михаил_Перович
Dievsky V.A. - Solution of task K2 variant 4 (K2-04)
Seller: Михаил_Перович
Solution K5 B1 termehu of Reshebnik Yablonsky AA 1978
Seller: TerMaster
C5 Option 04 termehu of Reshebnik Yablonsky AA 1978
Seller: TerMaster
Solution of task 3.2.6 from the collection of Kepe OE
Seller: Михаил_Перович