DHS 18.2 - Option 30. Decisions Ryabushko AP
📂 Mathematics
👤 Massimo86
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1. Find the distribution of the said discrete CB X and its distribution function F (x). Calculate the expectation M (X), the variance of D (X) and standard deviation σ (X). Draw the graph of the distribution function F (x)
1.30. Held three independent measurements of the sample. The probability of making a mistake in each dimension is equal to 0.01; SW X - the number of errors in the measurements.
2. Dana distribution function F (x) DM X. Find the probability density function f (x), the expectation M (X), the variance of D (X), and the probability of hitting NE X on the interval [a; b]. Construct the graphs of the functions F (x) and f (x).
3. Solve the following problems.
3.30. Among the rice seeds 0,4% of weed seeds. The number of weeds in rice distributed by the Poisson law. Find the probability that a random selection of 5,000 seeds will be detected 5 weed seeds.
4. Solve the following problems.
4.30. The standard deviation of each of 2134 independent CB does not exceed 4. Assess the probability that the deviation of the arithmetic mean of the NE from the arithmetic mean of their mathematical expectations will not exceed 0.5.
1.30. Held three independent measurements of the sample. The probability of making a mistake in each dimension is equal to 0.01; SW X - the number of errors in the measurements.
2. Dana distribution function F (x) DM X. Find the probability density function f (x), the expectation M (X), the variance of D (X), and the probability of hitting NE X on the interval [a; b]. Construct the graphs of the functions F (x) and f (x).
3. Solve the following problems.
3.30. Among the rice seeds 0,4% of weed seeds. The number of weeds in rice distributed by the Poisson law. Find the probability that a random selection of 5,000 seeds will be detected 5 weed seeds.
4. Solve the following problems.
4.30. The standard deviation of each of 2134 independent CB does not exceed 4. Assess the probability that the deviation of the arithmetic mean of the NE from the arithmetic mean of their mathematical expectations will not exceed 0.5.
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