DHS 15.1 - Option 9. Decisions Ryabushko AP

📂 Mathematics 👤 Massimo86

Product Description

1. Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)

1.9. u (M) = 3xy2 + z2 - xyz, M1 (1, 1, 2), M2 (3, 1, 4)

2. Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.

 (P): 2x - y - 2z = -2

3. Calculate the surface integral of the second kind.

 where S - the outer surface of the cylinder x2 + y2 = 1, cut off by the plane z = 0, z = 5

4. Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.

4.9. and (M) = (x + y) i + 3yj + (y - z) k, (p): 2x - y - 2z = -2

Additional Information

Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones and PCs. In MS Word (doc format) sent additionally.
Price: $1.30
Seller: Massimo86
Category: Mathematics
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