45. Solution to Chemistry Problem
📂 Chemistry
👤 Derkach
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5. For the reactions C(graphite) CO2(g)=2CO(g)
C(graphite) H2O(g)=CO(g) H2(g)
the enthalpy change at 500 K is -173.6 and -133.9 kJ, respectively. Calculate the heat of reaction at constant pressure for the reaction
CO(g) H2O(g)=CO2(g) H2(g)
at 1000 K, if the molar heat capacities in the range of 298-1500 K are:
Cp CO=28.41 4.10*10-3 T – 0.46*105 T-2 J/(mol*K);
Cp H2O(g)=30.00 10.71*10-3 T 0.33*105 T-2 J/(mol*K);
Cp CO2=44.14 9.04*10-3 T – 8.53*105 T-2 J/(mol*K);
Cp H2=27.28 3.26*10-3 T 0.502*105 T-2 J/(mol*K).
C(graphite) H2O(g)=CO(g) H2(g)
the enthalpy change at 500 K is -173.6 and -133.9 kJ, respectively. Calculate the heat of reaction at constant pressure for the reaction
CO(g) H2O(g)=CO2(g) H2(g)
at 1000 K, if the molar heat capacities in the range of 298-1500 K are:
Cp CO=28.41 4.10*10-3 T – 0.46*105 T-2 J/(mol*K);
Cp H2O(g)=30.00 10.71*10-3 T 0.33*105 T-2 J/(mol*K);
Cp CO2=44.14 9.04*10-3 T – 8.53*105 T-2 J/(mol*K);
Cp H2=27.28 3.26*10-3 T 0.502*105 T-2 J/(mol*K).
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