Using the data from the (At a temperature T = 1500 K and normal pressure, the degree of dissociation of iodine J2 into J atoms is a = 0.26. How will this value change when the pressure is reduced by 10 times?), determine the degree of dissociation of iodine at a temperature T = 2000 K and pressure, 10 times higher than normal. The heat of reaction of iodine dissociation is QP = 1.44•105 J/mol.

Answer. Format gif