4. Solving a chemistry problem
📂 Coursework
👤 Derkach
Product Description
12. According to the dependence of the saturated vapor pressure on the temperature and density of a given substance A (dsolid and dl in kg / m3) at the triple point (tr.t.):
1) plot lgP versus 1/T;
2) determine the coordinates of the triple point from the graph;
3) calculate the average heat of evaporation and sublimation;
4) plot the dependence of saturated steam pressure on temperature;
5) determine the heat of fusion of a substance at the triple point temperature;
6) calculate dT/dp for the melting process at the triple point temperature;
7) calculate the melting point of the substance at pressure p, Pa;
8) calculate the change in entropy, Gibbs and Helmholtz energy, enthalpy and internal energy for the process of sublimation of 1 mol of substance at the triple point;
9) determine the number of thermodynamic degrees of freedom at the following values of temperature and pressure:
a) Ttr.t , ptr.t;
b) Tntc, p= 1.013 x 105 Pa;
c) Tntk, ptr.t
Option Solid state Liquid state Conditions
T,K R,Pa T,K R,Pa
12,183.2
188.0
196.2
199.2
203.7 333.3
586.5
1850
3000
5305 201
203.7
214
216
230.2
244.0 4665.6
5305
7198
7998
13328
21728 M=64
P=1000 .105 Pa
dtv =1600
j = 1560
1) plot lgP versus 1/T;
2) determine the coordinates of the triple point from the graph;
3) calculate the average heat of evaporation and sublimation;
4) plot the dependence of saturated steam pressure on temperature;
5) determine the heat of fusion of a substance at the triple point temperature;
6) calculate dT/dp for the melting process at the triple point temperature;
7) calculate the melting point of the substance at pressure p, Pa;
8) calculate the change in entropy, Gibbs and Helmholtz energy, enthalpy and internal energy for the process of sublimation of 1 mol of substance at the triple point;
9) determine the number of thermodynamic degrees of freedom at the following values of temperature and pressure:
a) Ttr.t , ptr.t;
b) Tntc, p= 1.013 x 105 Pa;
c) Tntk, ptr.t
Option Solid state Liquid state Conditions
T,K R,Pa T,K R,Pa
12,183.2
188.0
196.2
199.2
203.7 333.3
586.5
1850
3000
5305 201
203.7
214
216
230.2
244.0 4665.6
5305
7198
7998
13328
21728 M=64
P=1000 .105 Pa
dtv =1600
j = 1560
Additional Information
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