Solved integral of the form ∫(αx+β)e^(γx)dx
📂 Mathematics
👤 plati-goods
Product Description
Solving an indefinite integral of the form ∫(αx+β)e^(γx)dx by the method of integration by parts, where α takes the values ±1,±2,±3,±4,±5,…m; β takes the values ±1,±2,±3,±4,±5,…n; γ takes the values ±1,±2,±3,±4,±5,…p.
An example of solving integrals for α=1, β=−1, γ=2 is considered; α=2, β=3, γ=3; α=3, β=−4, γ=−2; α=4, β=2, γ=−3; α=−2, β=2, γ=−3; α=−3, β=−2, γ=4;
∫(αx+β)e^(γx)dx, ∫(x−1)e^(2x)dx, ∫(2x+3)e^(3x)dx, ∫(3x−4)e^(−2x )dx, ∫(4x+2)e^(−3x)dx, ∫(−2x+2)e^(−3x)dx, ∫(−3x−2)e^(4x)dx
The solution is in PDF format
An example of solving integrals for α=1, β=−1, γ=2 is considered; α=2, β=3, γ=3; α=3, β=−4, γ=−2; α=4, β=2, γ=−3; α=−2, β=2, γ=−3; α=−3, β=−2, γ=4;
∫(αx+β)e^(γx)dx, ∫(x−1)e^(2x)dx, ∫(2x+3)e^(3x)dx, ∫(3x−4)e^(−2x )dx, ∫(4x+2)e^(−3x)dx, ∫(−2x+2)e^(−3x)dx, ∫(−3x−2)e^(4x)dx
The solution is in PDF format
No Reviews Yet
Be the first to leave a review for this product!
Related Products
Option 12 DHS 9.2
Seller: Chelovek10000
IDZ 9.1 - Option 14. Decisions Ryabushko AP
Seller: Massimo86
IDZ 8.4 - Option 14. Decisions Ryabushko AP
Seller: Massimo86
IDZ Ryabushko 8.4 Variant 12
Seller: AlexJester147
IDZ 8.4 - Option 1. Decisions Ryabushko AP
Seller: Massimo86
IDZ Ryabushko 19.1 Variant 10
Seller: AlexJester147
IDZ Ryabushko 11.1 Variant 22
Seller: AlexJester147
IDZ Ryabushko 8.3 Variant 12
Seller: AlexJester147