Solution of task 124 of Chemistry Book Shimanovich 2003
📂 Chemistry
👤 Михаил_Перович
Product Description
124. The reaction proceeds according to the equation N2 + 3H2 = 2NH3.
The concentrations of the substances involved were: [N2] = 0.80 mol / l; [H2] = 1.5 mol / l; [NN3] = 0.10 mol / l.
Calculate the concentration of hydrogen and ammonia when [N2] = 0.5 mol / l.
The answer is: [NH3] = 0.70 mol / l; [H] = 0.60 mol / l.
The concentrations of the substances involved were: [N2] = 0.80 mol / l; [H2] = 1.5 mol / l; [NN3] = 0.10 mol / l.
Calculate the concentration of hydrogen and ammonia when [N2] = 0.5 mol / l.
The answer is: [NH3] = 0.70 mol / l; [H] = 0.60 mol / l.
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